Math 105: Topics in Mathematics |
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Lesson 2 : Measures of Central Tendency and Dispersion
Due Date:
See the Lecture Notes Site. IntroductionIn this lesson we define various numerical measures (constants) for data sets. These numerical measures summarize and describe the data. The average value of the data would be a common example. There are two broad classification of such numerical measures that are computed from the data:
A measure of central tendency represents an "average value." Mean, median, mode (if you already know these) are measures of central tendency. A measure of dispersion is a measure of how widely the data is scattered around. 2.1 Measure of Central Tendency: MeanThe most common measure of central tendencies is the mean or arithmetic mean. Definition. The mean
or the arithmetic mean of a set of data is
given by
If we denote a data value (i.e., the variable) by x and if n is the
size of the data, then the above formula is written as
where ∑ denotes summation.
If the data represents a sample, then the mean is called the sample
mean. Again, if x denotes the variable, the data is sometimes
denoted by x1,x2, ... ,xn and with
such notations the formula for the mean is written as
If you have not seen the notation ∑ before,
it simply means summation. For example,
When the frequency table of a data set is given, then we can use the frequency table to compute the mean of the original data. Let us consider the the following example: Example 2.1.1 To estimate the mean time taken to complete a three-mile drive by a race car, the race car did several time trials. The following are sample times taken (in seconds) to complete the laps:
Following is the frequency distribution of this data:
To compute the mean time of the original data,
we obviously, add all the data values
and divide by the data size 35. The frequency
distribution tells us that, in the data, 46 was present 1 time,
47 was present 1 time, 48 was present 3, times and so on. So, using
the frequency distribution, we compute the mean as follows :
More generally, when we compute the mean using the frequency table, the formula for the mean would be
where fi is the frequency of xi. Properties of the Mean
Example (effect of translation): Your teacher tells you that the mean score for the midterm in your class is 73. After you complained and requested a change, he agreed that all can add 7 points to their score. The new mean score is (old mean + 7) = 73 + 7 = 80. This is what we meant by "effect of translation." Example (effect of multiplication by c): Suppose you have some data x1, x2, ..., xn on salaries in an industry in the United States and the mean is $37000. On a certain day (March 21, 2011), 1 U.S. dollar = 0.976469 Canadian dollars (say c = 0.976469). So, in Canadian dollars the mean is 37000*c = 37000 x 0.976469=36129.35 Canadian Dollars. Similarly, any change of units (inches to feet or cm, minutes to seconds) are "multiplication by a constant c." 2.2 Other Measures of Central Tendency: Median, and Mode
The Median
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Use of Calculators (TI-84): |
---|
Entering your data
|
Sorting data and
computing the median
|
Computing the mean
if only raw data is given
|
Computing the mean
if the frequency table is given
|
Computing the
meadian
Do the same as above and scroll down. |
Problems on 2.2: Mean and Median
Exercise 2.2.1. The following is the price
(in dollars) of a stock (say, CISCO SYSTEMS) checked by a trader several
times on a particular day.
138 | 142 | 127 | 137 | 148 | 130 | 142 | 133 |
Find the median price and mean price observed by the trader.
Solution: Use TI-84.
Exercise 2.2.2. The following figures refer to the GPA of six
students.
3.0 | 3.3 | 3.1 | 3.0 | 3.1 | 3.1 |
Find the median and mean GPA.
Exercise 2.2.3. The following data give the lifetime (in days) of light bulbs.
138 | 952 | 980 | 967 | 992 | 197 | 215 | 157 |
Find the mean and median lifetime of these bulbs.
Solution: Use TI-84.
Exercise 2.2.4. An athlete ran an event 32
times. The following frequency table gives the time taken (in seconds)
by the athlete to complete the events.
Time (in seconds) | Frequency |
---|---|
26 | 3 |
27 | 6 |
28 | 5 |
29 | 6 |
30 | 9 |
31 | 3 |
Total | 32 |
Compute the mean and median time taken by the athlete.
Solution: Use TI-84.
Exercise 2.2.5. Following is data on the weight (in ounces), at birth, of 96 babies born in Lawrence Memorial Hospital in May 2000.
94 | 105 | 124 | 110 | 119 | 137 | 96 | 110 | 120 | 115 | 119 |
104 | 135 | 123 | 129 | 72 | 121 | 117 | 96 | 107 | 80 | 80 |
96 | 123 | 124 | 124 | 134 | 78 | 138 | 106 | 130 | 97 | 134 |
111 | 133 | 128 | 96 | 126 | 124 | 125 | 127 | 62 | 127 | 96 |
116 | 118 | 126 | 94 | 127 | 121 | 117 | 124 | 93 | 135 | 112 |
120 | 125 | 120 | 147 | 138 | 72 | 119 | 89 | 81 | 113 | 100 |
109 | 127 | 138 | 122 | 110 | 113 | 100 | 115 | 110 | 135 | 120 |
97 | 127 | 120 | 110 | 107 | 111 | 126 | 132 | 120 | 108 | 148 |
133 | 103 | 92 | 124 | 150 | 86 | 121 | 98 |
Compute the mean and median weight, at birth, of the babies.
Solution: Use TI-84.
Exercise 2.2.6. Following is data on the hourly wages (paid only in whole dollars) of 99 employees in an industry.
7 | 11 | 7 | 11 | 10 | 9 | 10 | 10 | 12 | 13 |
7 | 8 | 11 | 11 | 14 | 9 | 7 | 9 | 11 | 7 |
9 | 13 | 12 | 14 | 7 | 8 | 7 | 14 | 15 | 9 |
9 | 7 | 11 | 9 | 12 | 9 | 12 | 11 | 14 | 9 |
12 | 13 | 7 | 9 | 10 | 14 | 11 | 12 | 13 | 7 |
15 | 15 | 16 | 16 | 15 | 16 | 11 | 7 | 18 | 19 |
15 | 16 | 15 | 15 | 16 | 16 | 17 | 16 | 16 | 13 |
15 | 15 | 16 | 15 | 16 | 15 | 15 | 17 | 16 | 12 |
16 | 15 | 15 | 16 | 15 | 15 | 19 | 8 | 16 | 17 |
16 | 16 | 15 | 16 | 16 | 16 | 13 | 12 | 8 |
Compute the mean and median hourly wage.
Solution: Use TI-84.
Exercise 2.2.7. Following is the frequency table on the number of typos in a sample of 30 books published by a publisher.
No. of Typos | 156 | 158 | 159 | 160 | 162 |
---|---|---|---|---|---|
Frequency | 6 | 4 | 5 | 6 | 9 |
Find the mean and median number of typos in a book.
Solution: Use TI-84.
Exercise 2.2.8. Following is data on the length (in inches), at birth, of 96 babies born in Lawrence Memorial Hospital in May 2000.
18 | 18.5 | 19 | 18.5 | 19 | 21 | 18 | 19 | 20 | 20.5 |
19 | 19 | 21.5 | 19.5 | 20 | 17 | 20 | 20 | 19 | 20.5 |
18 | 18.5 | 20 | 19.5 | 20.75 | 20 | 21 | 18 | 20.5 | 20 |
21 | 19 | 20.5 | 19 | 20 | 19.5 | 17.75 | 20 | 19.5 | 20 |
20.5 | 17 | 21 | 18.5 | 20 | 20 | 20 | 18.5 | 19.5 | 19 |
18 | 20.5 | 18 | 20 | 19 | 19 | 19.5 | 20 | 20.75 | 21 |
17.75 | 19 | 18 | 19 | 20 | 18.5 | 20 | 19 | 21 | 19 |
19.5 | 20 | 20 | 19 | 19.5 | 20 | 19.5 | 18.5 | 20.5 | 19.5 |
20.25 | 20 | 19.5 | 19.5 | 20 | 20 | 20 | 21 | 20 | 19 |
18.5 | 20.5 | 21.5 | 18 | 19.5 | 18 |
Compute the mean and median length, at birth, of these babies.
Solution: Use TI-84.
Example 2.3.1. Suppose two sections of the statistics class have the following percentage score distribution at the end of the semester:
Section A | 81 | 84 | 83 | 80 | 82 |
---|---|---|---|---|---|
Section B | 72 | 93 | 92 | 82 | 71 |
Both these sections have the same mean—82.
Medians of both the sets are same —82.
But the data sets are differently dispersed.
In Section A, everybody
will get a B grade. In section B, we will have two C's, one B and two
A's.
The measure of dispersion is a measure of how widely the data is scattered around. In section A, the data has a very small dispersion or variability, whereas section B has a large dispersion.
A very simple measure of dispersion is the range of the data, defined as:
range = largest value - smallest value.
Mean Deviation, Sample Variance, and Standard Deviation
We will discuss three more measures of dispersion.
Suppose we have a data set x1, x2, ... , xn of size n. We will denote the mean of the data by x. Three definitions follow:
Definition. The mean deviation of the data is defined as follows.
mean deviation = ( |x1- x
| + ... + |xn- x
|) / n
So, the mean deviation is the mean of the absolute deviations | xi -x | from the mean.
Definition. The sample
variance s2 of the data is
defined as follows:
s2 = [ (x1- x)2
+ ... + (xn- x)2
] / (n -1)
Remark.
Definition. The sample
standard deviation
is defined as the square root of the sample
variance s2. So, to compute the sample standard deviation,
we have to compute the sample variance first.
If we simplify the definition of sample variance we get the following
formula:
s2 =[ (x12 + x22
+ ... + xn2) - nx2]/(n
- 1)
We do some computations with the above example 2.3.1.
The mean deviation for section A = (1+2+1+2+0)/5= 6/5 and the mean deviation for section B = (10+11+10+0+11)/5= 42/5. Since the variability of section B was clearly higher, the mean deviation is also so.
Let us compute the the sample variances :
For section A the sample variance is
[ (81-82)2+(84-82)2+(83-82)2+(80-82)2+(82-82)2
]/(5-1) =
(1+4+1+4+0) /4= 10/4 = 2.5 .
For section B the sample variance is
[ (72-82)2+(93-82)2+(92-82)2+(82-82)2+(71-82)2
]/(5-1) =
(100+121+100+0+121) /4= 442/4.
Question: What does it mean when the variance or mean deviation of some data is zero? The answer is that all the data members are EQUAL!
Use of the Frequency Table
When a frequency table is given, we can use new formulas to compute the mean and variance of the data.
Formulas. Suppose the data consisting of n
observations is given in a frequency table (ungrouped). Let xi
denote the values and fi be the frequency of xi.
Then
x |
= |
|
= |
n |
, |
s2 = |
n- 1 |
, |
s2 = | 1
n- 1 |
[∑ |
(fixi2) -
n x2 |
]. |
Example 2.3.2. The following table extends the frequency table of the time taken to complete a lap by a race car (example 2.1.1) to compute mean and variance using the above formulas.
Time x |
Frequency f |
fx | fx2 |
---|---|---|---|
46 | 1 | 46 | 2116 |
47 | 1 | 47 | 2209 |
48 | 3 | 144 | 6912 |
49 | 3 | 147 | 7203 |
50 | 4 | 200 | 10000 |
51 | 6 | 306 | 15606 |
52 | 4 | 208 | 10816 |
53 | 5 | 265 | 14045 |
54 | 5 | 270 | 14580 |
55 | 2 | 110 | 6050 |
56 | 1 | 56 | 3136 |
Total | 35 | 1799 | 92673 |
So, the mean x = 1799/35 =51.4 and variance
s2 = (92673 - 35x 51.42)/(35-1) = 6.0118.
Remark: When computing power was not in abundance (only 20 or 30 years ago), as it is now, we used to compute mean and variance using such tables to do the computations. Such methods are out of date by now. We use TI-84 or other tools now.
Example 2.3.3. Following is the class frequency distribution of the data on birth weight of some babies (exercise 1.2, Lesson 1):
Classes | Frequency f |
Class Mark x |
fx | fx2 |
---|---|---|---|---|
60.5-80.5 | 9 | 70.5 | 634.5 | 44732.25 |
80.5-100.5 | 20 | 90.5 | 1810 | 163805 |
100.5-120.5 | 25 | 110.5 | 2762.5 | 305256.25 |
120.5-140.5 | 37 | 130.5 | 4828.5 | 630119.25 |
140.5-160.5 | 8 | 150.5 | 1204 | 181202 |
Total | 99 | 11239.5 | 1325114.75 |
We can use the above formula to compute (approximate) variance and the standard deviation of the birth weight.
So, the mean x = 11239.5/99 = 113.53 and variance
s2 = (1325114.75 - 99 x 113.532)/(99-1) = 500.997.
Remarks.
Comment: We have had detailed discussions of various formulas for defining the mean, variance, and other constants. It is important to understand these concepts and formulas.
It is equally important to appreciate the value and necessity of using
calculators or other available software (like Excel). It is almost impossible
(and unnecessary) to compute these constants manually and correctly, unless
one is specially gifted with numerical computations.
Use of Calculators (TI-84): |
---|
Computing the variance
and standard deviation
|
Problems on 2.3: Variance, Standard Deviation, and Use of the Frequency Table
Exercise 2.3.1. The following is the price (in dollars) of a stock (say, CISCO SYSTEMS) checked by a trader several times on a particular day.
138 | 142 | 127 | 137 | 148 | 130 | 142 | 133 |
Find the variance and standard deviation of the price.
Solution: Use TI-84.
Exercise 2.3.2. The following figures refer to the GPA of six students.
3.0 | 3.3 | 3.1 | 3.0 | 3.1 | 3.1 |
Find the variance and standard deviation of GPA.
Exercise 2.3.3. The following data give the lifetime (in days) of certain light bulbs.
138 | 952 | 980 | 967 | 992 | 197 | 215 | 157 |
Find the variance and standard deviation of the lifetime of these
bulbs.
Solution: Use TI-84.
Exercise 2.3.4. An athlete ran an event 32 times. The following frequency table gives the time taken (in seconds) by the athlete to complete the events.
Time (in seconds) | Frequency |
---|---|
26 | 3 |
27 | 6 |
28 | 5 |
29 | 6 |
30 | 9 |
31 | 3 |
Total | 32 |
Compute the variance and standard deviation of time taken by the athlete.
Solution: Use TI-84.
Also see
Solution to understand the use of formula.
Exercise 2.3.5. Following is data on the weight (in ounces), at birth, of 96 babies born in Lawrence Memorial Hospital in May 2000.
94 | 105 | 124 | 110 | 119 | 137 | 96 | 110 | 120 | 115 | 119 |
104 | 135 | 123 | 129 | 72 | 121 | 117 | 96 | 107 | 80 | 80 |
96 | 123 | 124 | 124 | 134 | 78 | 138 | 106 | 130 | 97 | 134 |
111 | 133 | 128 | 96 | 126 | 124 | 125 | 127 | 62 | 127 | 96 |
116 | 118 | 126 | 94 | 127 | 121 | 117 | 124 | 93 | 135 | 112 |
120 | 125 | 120 | 147 | 138 | 72 | 119 | 89 | 81 | 113 | 100 |
109 | 127 | 138 | 122 | 110 | 113 | 100 | 115 | 110 | 135 | 120 |
97 | 127 | 120 | 110 | 107 | 111 | 126 | 132 | 120 | 108 | 148 |
133 | 103 | 92 | 124 | 150 | 86 | 121 | 98 |
Compute the variance and standard deviation of the weight, at birth,
of these babies.
Solution: Use TI-84.
Also see
Solution
to understand the use of formula.
Exercise 2.3.6. Following is data on the hourly wages (paid only in whole dollars) of 99 employees in an industry.
7 | 11 | 7 | 11 | 10 | 9 | 10 | 10 | 12 | 13 |
7 | 8 | 11 | 11 | 14 | 9 | 7 | 9 | 11 | 7 |
9 | 13 | 12 | 14 | 7 | 8 | 7 | 14 | 15 | 9 |
9 | 7 | 11 | 9 | 12 | 9 | 12 | 11 | 14 | 9 |
12 | 13 | 7 | 9 | 10 | 14 | 11 | 12 | 13 | 7 |
15 | 15 | 16 | 16 | 15 | 16 | 11 | 7 | 18 | 19 |
15 | 16 | 15 | 15 | 16 | 16 | 17 | 16 | 16 | 13 |
15 | 15 | 16 | 15 | 16 | 15 | 15 | 17 | 16 | 12 |
16 | 15 | 15 | 16 | 15 | 15 | 19 | 8 | 16 | 17 |
16 | 16 | 15 | 16 | 16 | 16 | 13 | 12 | 8 |
Compute the variance and standard deviation of the hourly wages.
Solution: Use TI-84.
Exercise 2.3.7. Following is the frequency table on the number of typos in a sample of 30 books published by a publisher.
No. of Typos | 156 | 158 | 159 | 160 | 162 |
---|---|---|---|---|---|
Frequency | 6 | 4 | 5 | 6 | 9 |
Find the mean number, variance, and standard deviation of typos in
a book.
Solution: Use TI-84.
Exercise 2.3.8. Following is data on the length (in inches), at birth, of 96 babies born in Lawrence Memorial Hospital in May 2000.
18 | 18.5 | 19 | 18.5 | 19 | 21 | 18 | 19 | 20 | 20.5 |
19 | 19 | 21.5 | 19.5 | 20 | 17 | 20 | 20 | 19 | 20.5 |
18 | 18.5 | 20 | 19.5 | 20.75 | 20 | 21 | 18 | 20.5 | 20 |
21 | 19 | 20.5 | 19 | 20 | 19.5 | 17.75 | 20 | 19.5 | 20 |
20.5 | 17 | 21 | 18.5 | 20 | 20 | 20 | 18.5 | 19.5 | 19 |
18 | 20.5 | 18 | 20 | 19 | 19 | 19.5 | 20 | 20.75 | 21 |
17.75 | 19 | 18 | 19 | 20 | 18.5 | 20 | 19 | 21 | 19 |
19.5 | 20 | 20 | 19 | 19.5 | 20 | 19.5 | 18.5 | 20.5 | 19.5 |
20.25 | 20 | 19.5 | 19.5 | 20 | 20 | 20 | 21 | 20 | 19 |
18.5 | 20.5 | 21.5 | 18 | 19.5 | 18 |
Compute the variance and standard deviation of the length, at birth,
of these babies.
Solution: Use TI-84.
Exercise 2.3.9. The following is the frequency table of weight (in pounds) of some salmon in a river. Find the variance and standard deviation.
Weight x | 31 | 32 | 33 | 34 | 35 | 36 | 37 |
---|---|---|---|---|---|---|---|
Frequency f | 3 | 2 | 4 | 5 | 6 | 5 | 9 |
Find the variance and the standard deviation.
Solution: Use TI-84.
Also see
Solution
Exercise 2.3.10. The following data represents the time (in minutes) taken by students to drive to campus.
23 | 17 | 19 | 24 | 42 | 33 | 20 | 22 | 15 | 9 |
26 | 37 | 29 | 19 | 35 | 18 | 30 | 21 | 11 | 23 |
13 | 27 | 32 | 32 | 23 | 35 | 25 | 33 | 24 | 23 |
Find the mean, variance, and the standard deviation of the data.
Solution: Use TI-84.